$$\frac{2}{\frac{1}{3}-\frac{t}{3}}$$
$\frac{6}{1-t}$
$$\frac{2}{\frac{1+t}{3}}$$
$$\frac{2\times 3}{1+t}$$
$$\frac{6}{1+t}$$
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$\frac{6}{\left(1-t\right)^{2}}$
