Solve 9 ( b) 2/- 5, - 3/7, - 1/- 9, 7/- 10 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\frac { 2 } { - 5 } , \frac { - 3 } { 7 } , \frac { - 1 } { - 9 } , \frac { 7 } { - 10 }$$

Sort

$-\frac{7}{10},-\frac{3}{7},-\frac{2}{5},\frac{1}{9}$

Solution Steps

Fraction $\frac{2}{-5}$ can be rewritten as $-\frac{2}{5}$ by extracting the negative sign.

$$sort(-\frac{2}{5},\frac{-3}{7},\frac{-1}{-9},\frac{7}{-10})$$

Fraction $\frac{-3}{7}$ can be rewritten as $-\frac{3}{7}$ by extracting the negative sign.

$$sort(-\frac{2}{5},-\frac{3}{7},\frac{-1}{-9},\frac{7}{-10})$$

Fraction $\frac{-1}{-9}$ can be simplified to $\frac{1}{9}$ by removing the negative sign from both the numerator and the denominator.

$$sort(-\frac{2}{5},-\frac{3}{7},\frac{1}{9},\frac{7}{-10})$$

Fraction $\frac{7}{-10}$ can be rewritten as $-\frac{7}{10}$ by extracting the negative sign.

$$sort(-\frac{2}{5},-\frac{3}{7},\frac{1}{9},-\frac{7}{10})$$

Least common denominator of the numbers in the list $-\frac{2}{5},-\frac{3}{7},\frac{1}{9},-\frac{7}{10}$ is $630$. Convert numbers in the list to fractions with denominator $630$.

$$-\frac{252}{630},-\frac{270}{630},\frac{70}{630},-\frac{441}{630}$$

To sort the list, start from a single element $-\frac{252}{630}$.

$$-\frac{252}{630}$$

Insert $-\frac{270}{630}$ to the appropriate location in the new list.

$$-\frac{270}{630},-\frac{252}{630}$$

Insert $\frac{70}{630}$ to the appropriate location in the new list.

$$-\frac{270}{630},-\frac{252}{630},\frac{70}{630}$$

Insert $-\frac{441}{630}$ to the appropriate location in the new list.

$$-\frac{441}{630},-\frac{270}{630},-\frac{252}{630},\frac{70}{630}$$

Replace the obtained fractions with the initial values.

$$-\frac{7}{10},-\frac{3}{7},-\frac{2}{5},\frac{1}{9}$$

Evaluate

$-\frac{2}{5},-\frac{3}{7},\frac{1}{9},-\frac{7}{10}$