Question

$$\frac{2}{\sqrt{3}+\sqrt{5}}=\frac{a\sqrt{3}-b\sqrt{5}}{c}$$

Solve for a

$a=\frac{\sqrt{15}b+\sqrt{15}c-3c}{3}$
$c\neq 0$

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Solve for b

$b=\frac{\sqrt{15}\left(a+c\right)-5c}{5}$
$c\neq 0$

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