Factor out the common term \(2\).
\[\frac{2}{x+1}-\frac{3}{2(x+1)}=\frac{1}{2x+3}\]
Simplify \(\frac{2}{x+1}-\frac{3}{2(x+1)}\) to \(\frac{1}{2(x+1)}\).
\[\frac{1}{2(x+1)}=\frac{1}{2x+3}\]
Cross multiply.
\[2x+3=2(x+1)\]
Expand.
\[2x+3=2x+2\]
Cancel \(2x\) on both sides.
\[3=2\]
Since \(3=2\) is false, there is no solution.
[No Solution]
