Question

$$\frac { 2 \cdot 4 a ^ { 3 } + 11 a ^ { 2 } } { 49 }$$

Answer

$$(Ex*e^2*p*r*s*o*a^2*(8*a+11))/49$$

Solution


Simplify  \(2\times 4{a}^{3}\)  to  \(8{a}^{3}\).
\[Expereso\times \frac{8{a}^{3}+11{a}^{2}}{49}\]
Factor out the common term \({a}^{2}\).
\[Expereso\times \frac{{a}^{2}(8a+11)}{49}\]
Use this rule: \(\frac{a}{b} \times \frac{c}{d}=\frac{ac}{bd}\).
\[\frac{Expereso{a}^{2}(8a+11)}{49}\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[\frac{Exp{e}^{2}rso{a}^{2}(8a+11)}{49}\]
Regroup terms.
\[\frac{Ex{e}^{2}prso{a}^{2}(8a+11)}{49}\]