Question

$$\frac{2\gamma(x)}{3}=\frac{1dl+3}{15}$$

Solve for d (complex solution)

$\left\{\begin{matrix}d=-\frac{3-10x\gamma }{l}\text{, }&l\neq 0\\d\in \mathrm{C}\text{, }&\gamma =\frac{3}{10x}\text{ and }x\neq 0\text{ and }l=0\end{matrix}\right.$

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Solve for l (complex solution)

$\left\{\begin{matrix}l=-\frac{3-10x\gamma }{d}\text{, }&d\neq 0\\l\in \mathrm{C}\text{, }&\gamma =\frac{3}{10x}\text{ and }x\neq 0\text{ and }d=0\end{matrix}\right.$

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Solve for d

$\left\{\begin{matrix}d=-\frac{3-10x\gamma }{l}\text{, }&l\neq 0\\d\in \mathrm{R}\text{, }&\gamma =\frac{3}{10x}\text{ and }x\neq 0\text{ and }l=0\end{matrix}\right.$

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Solve for l

$\left\{\begin{matrix}l=-\frac{3-10x\gamma }{d}\text{, }&d\neq 0\\l\in \mathrm{R}\text{, }&\gamma =\frac{3}{10x}\text{ and }x\neq 0\text{ and }d=0\end{matrix}\right.$

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