Question

$$\frac{2-2}{x^{2}-8y-3}=\frac{2-3}{x^{2}-8y-3}$$

Answer

[No Solution]

Solution


Cancel \({x}^{2}-8y-3\) on both sides.
\[2-2=2-3\]
Simplify  \(2-2\)  to  \(0\).
\[0=2-3\]
Simplify  \(2-3\)  to  \(-1\).
\[0=-1\]
Since \(0=-1\) is false, there is no solution.
No Solution