Use Rule of One: \({x}^{1}=x\).
\[2+con\times 30-to{m}^{{230}^{}}=q\]
Regroup terms.
\[2+30con-to{m}^{{230}^{}}=q\]
Subtract \(2\) from both sides.
\[30con-to{m}^{{230}^{}}=q-2\]
Factor out the common term \(o\).
\[o(30cn-t{m}^{{230}^{}})=q-2\]
Divide both sides by \(o\).
\[30cn-t{m}^{{230}^{}}=\frac{q-2}{o}\]
Add \(t{m}^{{230}^{}}\) to both sides.
\[30cn=\frac{q-2}{o}+t{m}^{{230}^{}}\]
Divide both sides by \(30\).
\[cn=\frac{\frac{q-2}{o}+t{m}^{{230}^{}}}{30}\]
Simplify \(\frac{\frac{q-2}{o}+t{m}^{{230}^{}}}{30}\) to \(\frac{\frac{q-2}{o}}{30}+\frac{t{m}^{{230}^{}}}{30}\).
\[cn=\frac{\frac{q-2}{o}}{30}+\frac{t{m}^{{230}^{}}}{30}\]
Simplify \(\frac{\frac{q-2}{o}}{30}\) to \(\frac{q-2}{30o}\).
\[cn=\frac{q-2}{30o}+\frac{t{m}^{{230}^{}}}{30}\]
Divide both sides by \(n\).
\[c=\frac{\frac{q-2}{30o}+\frac{t{m}^{{230}^{}}}{30}}{n}\]
c=((q-2)/(30*o)+(t*m^230^)/30)/n
