Question

$$\frac{ 2+ \sqrt{ 3 } }{ x } = \frac{ x }{ 2- \sqrt{ 3 } }$$

Answer

x=1,-1

Solution


Cross multiply.
\[(2+\sqrt{3})(2-\sqrt{3})=xx\]
Use Difference of Squares: \({a}^{2}-{b}^{2}=(a+b)(a-b)\).
\[{2}^{2}-{\sqrt{3}}^{2}=xx\]
Simplify  \({2}^{2}\)  to  \(4\).
\[4-{\sqrt{3}}^{2}=xx\]
Use this rule: \({\sqrt{x}}^{2}=x\).
\[4-3=xx\]
Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[4-3={x}^{2}\]
Simplify  \(4-3\)  to  \(1\).
\[1={x}^{2}\]
Take the square root of both sides.
\[\pm \sqrt{1}=x\]
Simplify  \(\sqrt{1}\)  to  \(1\).
\[\pm 1=x\]
Switch sides.
\[x=\pm 1\]