1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2 12 58 | Equatix

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Question

$$\frac { 20 } { 9 } \times \frac { 2 } { 6 } \times \frac { 12 } { 58 }$$

$\frac{40}{261}\approx 0.153256705$

Reduce the fraction $\frac{2}{6}$ to lowest terms by extracting and canceling out $2$.

$$\frac{20}{9}\times \frac{1}{3}\times \frac{12}{58}$$

Multiply $\frac{20}{9}$ times $\frac{1}{3}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{20\times 1}{9\times 3}\times \frac{12}{58}$$

Do the multiplications in the fraction $\frac{20\times 1}{9\times 3}$.

$$\frac{20}{27}\times \frac{12}{58}$$

Reduce the fraction $\frac{12}{58}$ to lowest terms by extracting and canceling out $2$.

$$\frac{20}{27}\times \frac{6}{29}$$

Multiply $\frac{20}{27}$ times $\frac{6}{29}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{20\times 6}{27\times 29}$$

Do the multiplications in the fraction $\frac{20\times 6}{27\times 29}$.

$$\frac{120}{783}$$

Reduce the fraction $\frac{120}{783}$ to lowest terms by extracting and canceling out $3$.

$$\frac{40}{261}$$

$\frac{2 ^ {3} \cdot 5}{3 ^ {2} \cdot 29} = 0.1532567049808429$