How to solve (2150)/(1000)

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (2150)/(1000) | Equatix

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Question

$$\frac{ 2150 }{ 1000 }$$

Evaluate

$\frac{43}{20}=2.15$

Steps For Long Division Method

Use the $1^{st}$ digit $2$ from dividend $2150$

$$\begin{array}{l}\phantom{1000)}\phantom{1}\\1000\overline{)2150}\\\end{array}$$

Since $2$ is less than $1000$, use the next digit $1$ from dividend $2150$ and add $0$ to the quotient

$$\begin{array}{l}\phantom{1000)}0\phantom{2}\\1000\overline{)2150}\\\end{array}$$

Use the $2^{nd}$ digit $1$ from dividend $2150$

$$\begin{array}{l}\phantom{1000)}0\phantom{3}\\1000\overline{)2150}\\\end{array}$$

Since $21$ is less than $1000$, use the next digit $5$ from dividend $2150$ and add $0$ to the quotient

$$\begin{array}{l}\phantom{1000)}00\phantom{4}\\1000\overline{)2150}\\\end{array}$$

Use the $3^{rd}$ digit $5$ from dividend $2150$

$$\begin{array}{l}\phantom{1000)}00\phantom{5}\\1000\overline{)2150}\\\end{array}$$

Since $215$ is less than $1000$, use the next digit $0$ from dividend $2150$ and add $0$ to the quotient

$$\begin{array}{l}\phantom{1000)}000\phantom{6}\\1000\overline{)2150}\\\end{array}$$

Use the $4^{th}$ digit $0$ from dividend $2150$

$$\begin{array}{l}\phantom{1000)}000\phantom{7}\\1000\overline{)2150}\\\end{array}$$

Find closest multiple of $1000$ to $2150$. We see that $2 \times 1000 = 2000$ is the nearest. Now subtract $2000$ from $2150$ to get reminder $150$. Add $2$ to quotient.

$$\begin{array}{l}\phantom{1000)}0002\phantom{8}\\1000\overline{)2150}\\\phantom{1000)}\underline{\phantom{}2000\phantom{}}\\\phantom{1000)9}150\\\end{array}$$

Since $150$ is less than $1000$, stop the division. The reminder is $150$. The topmost line $0002$ is the quotient. Remove all zeros at the start of the quotient to get the actual quotient $2$.

$$\text{Quotient: }2$$ $$\text{Reminder: }150$$

Show Solution

Factor

$\frac{43}{2 ^ {2} \cdot 5} = 2\frac{3}{20} = 2.15$