How to solve 24/40 * 21/40

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 24/40 * 21/40 | Equatix

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$$\frac{24}{40}\times\frac{21}{40}$$

$\frac{63}{200}=0.315$

Reduce the fraction $\frac{24}{40}$ to lowest terms by extracting and canceling out $8$.

$$\frac{3}{5}\times \frac{21}{40}$$

Multiply $\frac{3}{5}$ times $\frac{21}{40}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 21}{5\times 40}$$

Do the multiplications in the fraction $\frac{3\times 21}{5\times 40}$.

$$\frac{63}{200}$$

$\frac{3 ^ {2} \cdot 7}{2 ^ {3} \cdot 5 ^ {2}} = 0.315$