$$\frac { 25 } { 4 } + \frac { 17 } { 12 } + \frac { 34 } { 9 }$$
$\frac{103}{9}\approx 11.444444444$
$$\frac{75}{12}+\frac{17}{12}+\frac{34}{9}$$
$$\frac{75+17}{12}+\frac{34}{9}$$
$$\frac{92}{12}+\frac{34}{9}$$
$$\frac{23}{3}+\frac{34}{9}$$
$$\frac{69}{9}+\frac{34}{9}$$
$$\frac{69+34}{9}$$
$$\frac{103}{9}$$
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$\frac{103}{3 ^ {2}} = 11\frac{4}{9} = 11.444444444444445$
