How to solve (25)/(80) imes100

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (25)/(80)\times100 | Equatix

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$$\frac{ 25 }{ 80 } \times 100$$

$\frac{125}{4}=31.25$

Reduce the fraction $\frac{25}{80}$ to lowest terms by extracting and canceling out $5$.

$$\frac{5}{16}\times 100$$

Express $\frac{5}{16}\times 100$ as a single fraction.

$$\frac{5\times 100}{16}$$

Multiply $5$ and $100$ to get $500$.

$$\frac{500}{16}$$

Reduce the fraction $\frac{500}{16}$ to lowest terms by extracting and canceling out $4$.

$$\frac{125}{4}$$

$\frac{5 ^ {3}}{2 ^ {2}} = 31\frac{1}{4} = 31.25$