Solve (25 - 5)/100 = (C + 0)/100 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\frac{25-5}{100}=\frac{C-0}{100}$$

Solve for C

$C=20$

Steps for Solving Linear Equation

Multiply both sides of the equation by $100$.

$$25-5=C-0$$

Subtract $5$ from $25$ to get $20$.

$$20=C-0$$

Swap sides so that all variable terms are on the left hand side.

$$C-0=20$$

Add $0$ to both sides.

$$C=20+0$$

Add $20$ and $0$ to get $20$.

$$C=20$$