Question

$$\frac{25\times t^{-4}}{5^{-3}\times10\times t^{-8}}(t\ne0)$$

Answer

0

Solution


Simplify  \(tne\times 0\)  to  \(0\).
\[25{t}^{-{45}^{-3}}\times 10{t}^{-8}\times 0\]
Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\[25{t}^{-(\frac{1}{{45}^{3}})}\times 10{t}^{-8}\times 0\]
Simplify  \({45}^{3}\)  to  \(91125\).
\[25{t}^{-(\frac{1}{91125})}\times 10{t}^{-8}\times 0\]
Simplify.
\[0\]