$$\frac{27-x^{3}}{9-x^{2}}$$
$\frac{x^{2}+3x+9}{x+3}$
$$\frac{\left(x-3\right)\left(-x^{2}-3x-9\right)}{\left(x-3\right)\left(-x-3\right)}$$
$$\frac{-x^{2}-3x-9}{-x-3}$$
Show Solution
Hide Solution
