Solve (2c - 5)/3 = (2c - 3)/5 | Equatix - Math Solver

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Example

3(r+2s)=2t-4

a⋅(b-2)=3b

3(r+2s)=2t-4

a⋅(b-2)=3b

Question

$$\frac{2c-5}{3}=\frac{2c-3}{5}$$

Solve for c

$c=4$

Steps for Solving Linear Equation

Multiply both sides of the equation by $15$, the least common multiple of $3,5$.

$$5\left(2c-5\right)=3\left(2c-3\right)$$

Use the distributive property to multiply $5$ by $2c-5$.

$$10c-25=3\left(2c-3\right)$$

Use the distributive property to multiply $3$ by $2c-3$.

$$10c-25=6c-9$$

Subtract $6c$ from both sides.

$$10c-25-6c=-9$$

Combine $10c$ and $-6c$ to get $4c$.

$$4c-25=-9$$

Add $25$ to both sides.

$$4c=-9+25$$

Add $-9$ and $25$ to get $16$.

$$4c=16$$

Divide both sides by $4$.

$$c=\frac{16}{4}$$

Divide $16$ by $4$ to get $4$.

$$c=4$$