How to solve 2s-1 2s+5 -2z1

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 2s-1 2s+5 -2z1 | Equatix

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Question

$$\frac{2s-1}{2s+5}-2z1$$

Evaluate

$\frac{-4sz_{1}-10z_{1}+2s-1}{2s+5}$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply $-2z_{1}$ times $\frac{2s+5}{2s+5}$.

$$\frac{2s-1}{2s+5}+\frac{-2z_{1}\left(2s+5\right)}{2s+5}$$

Since $\frac{2s-1}{2s+5}$ and $\frac{-2z_{1}\left(2s+5\right)}{2s+5}$ have the same denominator, add them by adding their numerators.

$$\frac{2s-1-2z_{1}\left(2s+5\right)}{2s+5}$$

Do the multiplications in $2s-1-2z_{1}\left(2s+5\right)$.

$$\frac{2s-1-4z_{1}s-10z_{1}}{2s+5}$$

Show Solution

Expand

$\frac{-4sz_{1}-10z_{1}+2s-1}{2s+5}$

Short Solution Steps

To add or subtract expressions, expand them to make their denominators the same. Multiply $-2z_{1}$ times $\frac{2s+5}{2s+5}$.

$$\frac{2s-1}{2s+5}+\frac{-2z_{1}\left(2s+5\right)}{2s+5}$$

Since $\frac{2s-1}{2s+5}$ and $\frac{-2z_{1}\left(2s+5\right)}{2s+5}$ have the same denominator, add them by adding their numerators.

$$\frac{2s-1-2z_{1}\left(2s+5\right)}{2s+5}$$

Do the multiplications in $2s-1-2z_{1}\left(2s+5\right)$.

$$\frac{2s-1-4z_{1}s-10z_{1}}{2s+5}$$

Show Solution

Basic Math

Pre-Algebra

Algebra

Trigonometry

Calculus

Precalculus

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Finite Math

Linear Algebra

Chemistry

Example

Question

Evaluate

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Short Solution Steps