Question

$$\frac{2x}{3}+\frac{1}{=\frac{7x}{16}+3$$

Answer

x=-1/53

Solution


Simplify  \(2x\times 3\)  to  \(6x\).
\[6x+1=7x\times 16+3\]
Simplify  \(7x\times 16\)  to  \(112x\).
\[6x+1=112x+3\]
Subtract \(6x\) from both sides.
\[1=112x+3-6x\]
Simplify  \(112x+3-6x\)  to  \(106x+3\).
\[1=106x+3\]
Subtract \(3\) from both sides.
\[1-3=106x\]
Simplify  \(1-3\)  to  \(-2\).
\[-2=106x\]
Divide both sides by \(106\).
\[-\frac{2}{106}=x\]
Simplify  \(\frac{2}{106}\)  to  \(\frac{1}{53}\).
\[-\frac{1}{53}=x\]
Switch sides.
\[x=-\frac{1}{53}\]

Decimal Form: -0.018868