To add or subtract expressions, expand them to make their denominators the same. Least common multiple of $\left(x-5\right)\left(x-4\right)$ and $\left(x-4\right)\left(x-3\right)$ is $\left(x-5\right)\left(x-4\right)\left(x-3\right)$. Multiply $\frac{2x-6}{\left(x-5\right)\left(x-4\right)}$ times $\frac{x-3}{x-3}$. Multiply $\frac{x-1}{\left(x-4\right)\left(x-3\right)}$ times $\frac{x-5}{x-5}$.
Since $\frac{\left(2x-6\right)\left(x-3\right)}{\left(x-5\right)\left(x-4\right)\left(x-3\right)}$ and $\frac{\left(x-1\right)\left(x-5\right)}{\left(x-5\right)\left(x-4\right)\left(x-3\right)}$ have the same denominator, subtract them by subtracting their numerators.
To add or subtract expressions, expand them to make their denominators the same. Least common multiple of $\left(x-5\right)\left(x-4\right)\left(x-3\right)$ and $\left(x-5\right)\left(x-3\right)$ is $\left(x-5\right)\left(x-4\right)\left(x-3\right)$. Multiply $\frac{x-2}{\left(x-5\right)\left(x-3\right)}$ times $\frac{x-4}{x-4}$.
Since $\frac{x^{2}-6x+13}{\left(x-5\right)\left(x-4\right)\left(x-3\right)}$ and $\frac{\left(x-2\right)\left(x-4\right)}{\left(x-5\right)\left(x-4\right)\left(x-3\right)}$ have the same denominator, subtract them by subtracting their numerators.
To add or subtract expressions, expand them to make their denominators the same. Least common multiple of $\left(x-5\right)\left(x-4\right)$ and $\left(x-4\right)\left(x-3\right)$ is $\left(x-5\right)\left(x-4\right)\left(x-3\right)$. Multiply $\frac{2x-6}{\left(x-5\right)\left(x-4\right)}$ times $\frac{x-3}{x-3}$. Multiply $\frac{x-1}{\left(x-4\right)\left(x-3\right)}$ times $\frac{x-5}{x-5}$.
Since $\frac{\left(2x-6\right)\left(x-3\right)}{\left(x-5\right)\left(x-4\right)\left(x-3\right)}$ and $\frac{\left(x-1\right)\left(x-5\right)}{\left(x-5\right)\left(x-4\right)\left(x-3\right)}$ have the same denominator, subtract them by subtracting their numerators.
To add or subtract expressions, expand them to make their denominators the same. Least common multiple of $\left(x-5\right)\left(x-4\right)\left(x-3\right)$ and $\left(x-5\right)\left(x-3\right)$ is $\left(x-5\right)\left(x-4\right)\left(x-3\right)$. Multiply $\frac{x-2}{\left(x-5\right)\left(x-3\right)}$ times $\frac{x-4}{x-4}$.
Since $\frac{x^{2}-6x+13}{\left(x-5\right)\left(x-4\right)\left(x-3\right)}$ and $\frac{\left(x-2\right)\left(x-4\right)}{\left(x-5\right)\left(x-4\right)\left(x-3\right)}$ have the same denominator, subtract them by subtracting their numerators.