$$\frac{ 2y-3 }{ 3 } =1- \frac{ 2 }{ 3 } x$$
$x=3-y$
$$2y-3=3-2x$$
$$3-2x=2y-3$$
$$-2x=2y-3-3$$
$$-2x=2y-6$$
$$\frac{-2x}{-2}=\frac{2y-6}{-2}$$
$$x=\frac{2y-6}{-2}$$
$$x=3-y$$
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$y=3-x$
$$2y=3-2x+3$$
$$2y=6-2x$$
$$\frac{2y}{2}=\frac{6-2x}{2}$$
$$y=\frac{6-2x}{2}$$
$$y=3-x$$