Question

$$\frac{ 3 { x }^{ 2 } \times 15 { y }^{ 4 } }{ 5 { y }^{ 2 } \times 9 { x }^{ 3 } }$$

Answer

$$y^2/x$$

Solution


Simplify  \(3{x}^{2}\times 15{y}^{4}\)  to  \(45{x}^{2}{y}^{4}\).
\[\frac{45{x}^{2}{y}^{4}}{5{y}^{2}\times 9{x}^{3}}\]
Simplify  \(5{y}^{2}\times 9{x}^{3}\)  to  \(45{y}^{2}{x}^{3}\).
\[\frac{45{x}^{2}{y}^{4}}{45{y}^{2}{x}^{3}}\]
Cancel \(45\).
\[\frac{{x}^{2}{y}^{4}}{{y}^{2}{x}^{3}}\]
Use Quotient Rule: \(\frac{{x}^{a}}{{x}^{b}}={x}^{a-b}\).
\[{x}^{2-3}{y}^{4-2}\]
Simplify  \(2-3\)  to  \(-1\).
\[{x}^{-1}{y}^{4-2}\]
Simplify  \(4-2\)  to  \(2\).
\[{x}^{-1}{y}^{2}\]
Use Negative Power Rule: \({x}^{-a}=\frac{1}{{x}^{a}}\).
\[\frac{1}{x}{y}^{2}\]
Simplify.
\[\frac{{y}^{2}}{x}\]