How to solve 3/10 + 7/15

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3/10 + 7/15 | Equatix

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$$\frac{3}{10}+\frac{7}{15}$$

$\frac{23}{30}\approx 0.766666667$

Least common multiple of $10$ and $15$ is $30$. Convert $\frac{3}{10}$ and $\frac{7}{15}$ to fractions with denominator $30$.

$$\frac{9}{30}+\frac{14}{30}$$

Since $\frac{9}{30}$ and $\frac{14}{30}$ have the same denominator, add them by adding their numerators.

$$\frac{9+14}{30}$$

Add $9$ and $14$ to get $23$.

$$\frac{23}{30}$$

$\frac{23}{2 \cdot 3 \cdot 5} = 0.7666666666666667$