How to solve (3)/(2)-3=0

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (3)/(2)-3=0 | Equatix

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3(r+2s)=2t-4

a⋅(b-2)=3b

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$$\frac{ 3 }{ 2 } -3=0$$

Verify

$\text{false}$

Solution Steps

Convert $3$ to fraction $\frac{6}{2}$.

$$\frac{3}{2}-\frac{6}{2}=0$$

Since $\frac{3}{2}$ and $\frac{6}{2}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{3-6}{2}=0$$

Subtract $6$ from $3$ to get $-3$.

$$-\frac{3}{2}=0$$

Compare $-\frac{3}{2}$ and $0$.

$$\text{false}$$

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