$$[\frac{3}{2}x+1]^{3}$$
$\frac{\left(3x+2\right)^{3}}{8}$
$$\frac{27}{8}x^{3}+\frac{27}{4}x^{2}+\frac{9}{2}x+1$$
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$\frac{27x^{3}}{8}+\frac{27x^{2}}{4}+\frac{9x}{2}+1$
