$$\frac{ 3 }{ 2ab } \times \frac{ 4 }{ 3ac }$$
$\frac{2}{bca^{2}}$
$$\frac{3\times 4}{2ab\times 3ac}$$
$$\frac{2}{aabc}$$
$$\frac{2}{a^{2}bc}$$
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$-\frac{2}{c\left(ab\right)^{2}}$
