How to solve |3/4 - 4/3|

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve |3/4 - 4/3| | Equatix

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$$|\frac{3}{4}-\frac{4}{3}|$$

$\frac{7}{12}\approx 0.583333333$

Least common multiple of $4$ and $3$ is $12$. Convert $\frac{3}{4}$ and $\frac{4}{3}$ to fractions with denominator $12$.

$$|\frac{9}{12}-\frac{16}{12}|$$

Since $\frac{9}{12}$ and $\frac{16}{12}$ have the same denominator, subtract them by subtracting their numerators.

$$|\frac{9-16}{12}|$$

Subtract $16$ from $9$ to get $-7$.

$$|-\frac{7}{12}|$$

The absolute value of a real number $a$ is $a$ when $a\geq 0$, or $-a$ when $a<0$. The absolute value of $-\frac{7}{12}$ is $\frac{7}{12}$.

$$\frac{7}{12}$$

$\frac{7}{2 ^ {2} \cdot 3} = 0.5833333333333334$