$$\frac{3}{4}(1+x)=\frac{1}{4}(5+x)$$
$x=1$
$$\frac{3}{4}+\frac{3}{4}x=\frac{1}{4}\left(5+x\right)$$
$$\frac{3}{4}+\frac{3}{4}x=\frac{1}{4}\times 5+\frac{1}{4}x$$
$$\frac{3}{4}+\frac{3}{4}x=\frac{5}{4}+\frac{1}{4}x$$
$$\frac{3}{4}+\frac{3}{4}x-\frac{1}{4}x=\frac{5}{4}$$
$$\frac{3}{4}+\frac{1}{2}x=\frac{5}{4}$$
$$\frac{1}{2}x=\frac{5}{4}-\frac{3}{4}$$
$$\frac{1}{2}x=\frac{5-3}{4}$$
$$\frac{1}{2}x=\frac{2}{4}$$
$$\frac{1}{2}x=\frac{1}{2}$$
$$x=\frac{1}{2}\times 2$$
$$x=1$$
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