$$\frac { 3 } { 4 } ( 7 x - 1 ) - ( 2 x - \frac { 1 - x } { 2 } ) = x + \frac { 3 } { 2 }$$
$x=1$
$$3\left(7x-1\right)-4\left(2x-\frac{1-x}{2}\right)=4x+6$$
$$21x-3-4\left(2x-\frac{1-x}{2}\right)=4x+6$$
$$21x-3-4\left(2x-\left(\frac{1}{2}-\frac{1}{2}x\right)\right)=4x+6$$
$$21x-3-4\left(2x-\frac{1}{2}-\left(-\frac{1}{2}x\right)\right)=4x+6$$
$$21x-3-4\left(2x-\frac{1}{2}+\frac{1}{2}x\right)=4x+6$$
$$21x-3-4\left(\frac{5}{2}x-\frac{1}{2}\right)=4x+6$$
$$21x-3-4\times \frac{5}{2}x-4\left(-\frac{1}{2}\right)=4x+6$$
$$21x-3+\frac{-4\times 5}{2}x-4\left(-\frac{1}{2}\right)=4x+6$$
$$21x-3+\frac{-20}{2}x-4\left(-\frac{1}{2}\right)=4x+6$$
$$21x-3-10x-4\left(-\frac{1}{2}\right)=4x+6$$
$$21x-3-10x+\frac{-4\left(-1\right)}{2}=4x+6$$
$$21x-3-10x+\frac{4}{2}=4x+6$$
$$21x-3-10x+2=4x+6$$
$$11x-3+2=4x+6$$
$$11x-1=4x+6$$
$$11x-1-4x=6$$
$$7x-1=6$$
$$7x=6+1$$
$$7x=7$$
$$x=\frac{7}{7}$$
$$x=1$$
Show Solution
Hide Solution
