$$\frac{ 3 }{ 4 } (y+8)= \frac{ 5 }{ 6 } (y+2)$$
$y=52$
$$\frac{3}{4}y+\frac{3}{4}\times 8=\frac{5}{6}\left(y+2\right)$$
$$\frac{3}{4}y+\frac{3\times 8}{4}=\frac{5}{6}\left(y+2\right)$$
$$\frac{3}{4}y+\frac{24}{4}=\frac{5}{6}\left(y+2\right)$$
$$\frac{3}{4}y+6=\frac{5}{6}\left(y+2\right)$$
$$\frac{3}{4}y+6=\frac{5}{6}y+\frac{5}{6}\times 2$$
$$\frac{3}{4}y+6=\frac{5}{6}y+\frac{5\times 2}{6}$$
$$\frac{3}{4}y+6=\frac{5}{6}y+\frac{10}{6}$$
$$\frac{3}{4}y+6=\frac{5}{6}y+\frac{5}{3}$$
$$\frac{3}{4}y+6-\frac{5}{6}y=\frac{5}{3}$$
$$-\frac{1}{12}y+6=\frac{5}{3}$$
$$-\frac{1}{12}y=\frac{5}{3}-6$$
$$-\frac{1}{12}y=\frac{5}{3}-\frac{18}{3}$$
$$-\frac{1}{12}y=\frac{5-18}{3}$$
$$-\frac{1}{12}y=-\frac{13}{3}$$
$$y=-\frac{13}{3}\left(-12\right)$$
$$y=\frac{-13\left(-12\right)}{3}$$
$$y=\frac{156}{3}$$
$$y=52$$
Show Solution
Hide Solution
