$$\frac{3}{4}+\frac{1}{3}+\frac{1}{2}$$
$\frac{19}{12}\approx 1.583333333$
$$\frac{9}{12}+\frac{4}{12}+\frac{1}{2}$$
$$\frac{9+4}{12}+\frac{1}{2}$$
$$\frac{13}{12}+\frac{1}{2}$$
$$\frac{13}{12}+\frac{6}{12}$$
$$\frac{13+6}{12}$$
$$\frac{19}{12}$$
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$\frac{19}{2 ^ {2} \cdot 3} = 1\frac{7}{12} = 1.5833333333333333$