$$\frac { 3 } { 4 } + \frac { 2 } { 3 } \times \frac { 5 } { 8 } = \frac { 5 } { 6 } - \frac { 1 } { 8 }$$
$\text{false}$
$$\frac{3}{4}+\frac{2\times 5}{3\times 8}=\frac{5}{6}-\frac{1}{8}$$
$$\frac{3}{4}+\frac{10}{24}=\frac{5}{6}-\frac{1}{8}$$
$$\frac{3}{4}+\frac{5}{12}=\frac{5}{6}-\frac{1}{8}$$
$$\frac{9}{12}+\frac{5}{12}=\frac{5}{6}-\frac{1}{8}$$
$$\frac{9+5}{12}=\frac{5}{6}-\frac{1}{8}$$
$$\frac{14}{12}=\frac{5}{6}-\frac{1}{8}$$
$$\frac{7}{6}=\frac{5}{6}-\frac{1}{8}$$
$$\frac{7}{6}=\frac{20}{24}-\frac{3}{24}$$
$$\frac{7}{6}=\frac{20-3}{24}$$
$$\frac{7}{6}=\frac{17}{24}$$
$$\frac{28}{24}=\frac{17}{24}$$
$$\text{false}$$
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