How to solve 3/4 + 7/12

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3/4 + 7/12 | Equatix

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$$\frac{3}{4}+\frac{7}{12}$$

$\frac{4}{3}\approx 1.333333333$

Least common multiple of $4$ and $12$ is $12$. Convert $\frac{3}{4}$ and $\frac{7}{12}$ to fractions with denominator $12$.

$$\frac{9}{12}+\frac{7}{12}$$

Since $\frac{9}{12}$ and $\frac{7}{12}$ have the same denominator, add them by adding their numerators.

$$\frac{9+7}{12}$$

Add $9$ and $7$ to get $16$.

$$\frac{16}{12}$$

Reduce the fraction $\frac{16}{12}$ to lowest terms by extracting and canceling out $4$.

$$\frac{4}{3}$$

$\frac{2 ^ {2}}{3} = 1\frac{1}{3} = 1.3333333333333333$