How to solve 3/4 * X * 8/18

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3/4 * X * 8/18 | Equatix

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Question

$$\frac{3}{4}X\frac{8}{18}$$

Evaluate

$\frac{X}{3}$

Solution Steps

Reduce the fraction $\frac{8}{18}$ to lowest terms by extracting and canceling out $2$.

$$\frac{3}{4}X\times \frac{4}{9}$$

Multiply $\frac{3}{4}$ times $\frac{4}{9}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 4}{4\times 9}X$$

Cancel out $4$ in both numerator and denominator.

$$\frac{3}{9}X$$

Reduce the fraction $\frac{3}{9}$ to lowest terms by extracting and canceling out $3$.

$$\frac{1}{3}X$$

Show Solution

Differentiate w.r.t. X

$\frac{1}{3} = 0.3333333333333333$

Steps Using Definition of a Derivative

Reduce the fraction $\frac{8}{18}$ to lowest terms by extracting and canceling out $2$.

$$\frac{\mathrm{d}}{\mathrm{d}X}(\frac{3}{4}X\times \frac{4}{9})$$

Multiply $\frac{3}{4}$ times $\frac{4}{9}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{\mathrm{d}}{\mathrm{d}X}(\frac{3\times 4}{4\times 9}X)$$

Cancel out $4$ in both numerator and denominator.

$$\frac{\mathrm{d}}{\mathrm{d}X}(\frac{3}{9}X)$$

Reduce the fraction $\frac{3}{9}$ to lowest terms by extracting and canceling out $3$.

$$\frac{\mathrm{d}}{\mathrm{d}X}(\frac{1}{3}X)$$

The derivative of $ax^{n}$ is $nax^{n-1}$.

$$\frac{1}{3}X^{1-1}$$

Subtract $1$ from $1$.

$$\frac{1}{3}X^{0}$$

For any term $t$ except $0$, $t^{0}=1$.

$$\frac{1}{3}\times 1$$

For any term $t$, $t\times 1=t$ and $1t=t$.

$$\frac{1}{3}$$