$$\frac{ 3 }{ 4 } x+2= \frac{ 1 }{ 3 } x+ \frac{ 1 }{ 2 }$$
$x = -\frac{18}{5} = -3\frac{3}{5} = -3.6$
$$\frac{3}{4}x+2-\frac{1}{3}x=\frac{1}{2}$$
$$\frac{5}{12}x+2=\frac{1}{2}$$
$$\frac{5}{12}x=\frac{1}{2}-2$$
$$\frac{5}{12}x=\frac{1}{2}-\frac{4}{2}$$
$$\frac{5}{12}x=\frac{1-4}{2}$$
$$\frac{5}{12}x=-\frac{3}{2}$$
$$x=-\frac{3}{2}\times \frac{12}{5}$$
$$x=\frac{-3\times 12}{2\times 5}$$
$$x=\frac{-36}{10}$$
$$x=-\frac{18}{5}$$
Show Solution
Hide Solution
