$$\frac{3}{4}x+\frac{1}{4}=1$$
$x=1$
$$\frac{3}{4}x=1-\frac{1}{4}$$
$$\frac{3}{4}x=\frac{4}{4}-\frac{1}{4}$$
$$\frac{3}{4}x=\frac{4-1}{4}$$
$$\frac{3}{4}x=\frac{3}{4}$$
$$x=\frac{3}{4}\times \frac{4}{3}$$
$$x=1$$
Show Solution
Hide Solution
