$$\frac { 3 } { 5 } 10 g =$$
$6g$
$$\frac{3\times 10}{5}g$$
$$\frac{30}{5}g$$
$$6g$$
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$6$
$$\frac{\mathrm{d}}{\mathrm{d}g}(\frac{3\times 10}{5}g)$$
$$\frac{\mathrm{d}}{\mathrm{d}g}(\frac{30}{5}g)$$
$$\frac{\mathrm{d}}{\mathrm{d}g}(6g)$$
$$6g^{1-1}$$
$$6g^{0}$$
$$6\times 1$$
$$6$$