How to solve 3/5 + 2/10 - 1/20

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3/5 + 2/10 - 1/20 | Equatix

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Question

$$\frac{3}{5}+\frac{2}{10}-\frac{1}{20}$$

Evaluate

$\frac{3}{4}=0.75$

Solution Steps

Reduce the fraction $\frac{2}{10}$ to lowest terms by extracting and canceling out $2$.

$$\frac{3}{5}+\frac{1}{5}-\frac{1}{20}$$

Since $\frac{3}{5}$ and $\frac{1}{5}$ have the same denominator, add them by adding their numerators.

$$\frac{3+1}{5}-\frac{1}{20}$$

Add $3$ and $1$ to get $4$.

$$\frac{4}{5}-\frac{1}{20}$$

Least common multiple of $5$ and $20$ is $20$. Convert $\frac{4}{5}$ and $\frac{1}{20}$ to fractions with denominator $20$.

$$\frac{16}{20}-\frac{1}{20}$$

Since $\frac{16}{20}$ and $\frac{1}{20}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{16-1}{20}$$

Subtract $1$ from $16$ to get $15$.

$$\frac{15}{20}$$

Reduce the fraction $\frac{15}{20}$ to lowest terms by extracting and canceling out $5$.

$$\frac{3}{4}$$

Show Solution

Factor

$\frac{3}{2 ^ {2}} = 0.75$