How to solve 3/5 + 3/4 + 6/10

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3/5 + 3/4 + 6/10 | Equatix

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Question

$$\frac{3}{5}+\frac{3}{4}+\frac{6}{10}$$

Evaluate

$\frac{39}{20}=1.95$

Solution Steps

Least common multiple of $5$ and $4$ is $20$. Convert $\frac{3}{5}$ and $\frac{3}{4}$ to fractions with denominator $20$.

$$\frac{12}{20}+\frac{15}{20}+\frac{6}{10}$$

Since $\frac{12}{20}$ and $\frac{15}{20}$ have the same denominator, add them by adding their numerators.

$$\frac{12+15}{20}+\frac{6}{10}$$

Add $12$ and $15$ to get $27$.

$$\frac{27}{20}+\frac{6}{10}$$

Reduce the fraction $\frac{6}{10}$ to lowest terms by extracting and canceling out $2$.

$$\frac{27}{20}+\frac{3}{5}$$

Least common multiple of $20$ and $5$ is $20$. Convert $\frac{27}{20}$ and $\frac{3}{5}$ to fractions with denominator $20$.

$$\frac{27}{20}+\frac{12}{20}$$

Since $\frac{27}{20}$ and $\frac{12}{20}$ have the same denominator, add them by adding their numerators.

$$\frac{27+12}{20}$$

Add $27$ and $12$ to get $39$.

$$\frac{39}{20}$$

Show Solution

Factor

$\frac{3 \cdot 13}{2 ^ {2} \cdot 5} = 1\frac{19}{20} = 1.95$