How to solve 3/5 + 4/3 + 6/9 =

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3/5 + 4/3 + 6/9 = | Equatix

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Question

$$\frac{3}{5}+\frac{4}{3}+\frac{6}{9}=$$

Evaluate

$\frac{13}{5}=2.6$

Solution Steps

Least common multiple of $5$ and $3$ is $15$. Convert $\frac{3}{5}$ and $\frac{4}{3}$ to fractions with denominator $15$.

$$\frac{9}{15}+\frac{20}{15}+\frac{6}{9}$$

Since $\frac{9}{15}$ and $\frac{20}{15}$ have the same denominator, add them by adding their numerators.

$$\frac{9+20}{15}+\frac{6}{9}$$

Add $9$ and $20$ to get $29$.

$$\frac{29}{15}+\frac{6}{9}$$

Reduce the fraction $\frac{6}{9}$ to lowest terms by extracting and canceling out $3$.

$$\frac{29}{15}+\frac{2}{3}$$

Least common multiple of $15$ and $3$ is $15$. Convert $\frac{29}{15}$ and $\frac{2}{3}$ to fractions with denominator $15$.

$$\frac{29}{15}+\frac{10}{15}$$

Since $\frac{29}{15}$ and $\frac{10}{15}$ have the same denominator, add them by adding their numerators.

$$\frac{29+10}{15}$$

Add $29$ and $10$ to get $39$.

$$\frac{39}{15}$$

Reduce the fraction $\frac{39}{15}$ to lowest terms by extracting and canceling out $3$.

$$\frac{13}{5}$$

Show Solution

Factor

$\frac{13}{5} = 2\frac{3}{5} = 2.6$