How to solve 3 + 7 3 28

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3 + 7 3 28 | Equatix

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$$\frac { 3 } { 7 } + \frac { 1 } { 4 } + \frac { 3 } { 28 }$$

$\frac{11}{14}\approx 0.785714286$

Least common multiple of $7$ and $4$ is $28$. Convert $\frac{3}{7}$ and $\frac{1}{4}$ to fractions with denominator $28$.

$$\frac{12}{28}+\frac{7}{28}+\frac{3}{28}$$

Since $\frac{12}{28}$ and $\frac{7}{28}$ have the same denominator, add them by adding their numerators.

$$\frac{12+7}{28}+\frac{3}{28}$$

Add $12$ and $7$ to get $19$.

$$\frac{19}{28}+\frac{3}{28}$$

Since $\frac{19}{28}$ and $\frac{3}{28}$ have the same denominator, add them by adding their numerators.

$$\frac{19+3}{28}$$

Add $19$ and $3$ to get $22$.

$$\frac{22}{28}$$

Reduce the fraction $\frac{22}{28}$ to lowest terms by extracting and canceling out $2$.

$$\frac{11}{14}$$

$\frac{11}{2 \cdot 7} = 0.7857142857142857$