Question

$$\frac{3}{7}+\frac{2}{7}+\frac{5}{6}+\frac{4}{6}+\frac{2}{3}$$

Evaluate

$\frac{121}{42}\approx 2.880952381$

Show Solution

Factor

$\frac{11 ^ {2}}{2 \cdot 3 \cdot 7} = 2\frac{37}{42} = 2.880952380952381$