How to solve 3/7 - 7/5

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3/7 - 7/5 | Equatix

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$$\frac{3}{7}+\frac{-7}{5}$$

$-\frac{34}{35}\approx -0.971428571$

Fraction $\frac{-7}{5}$ can be rewritten as $-\frac{7}{5}$ by extracting the negative sign.

$$\frac{3}{7}-\frac{7}{5}$$

Least common multiple of $7$ and $5$ is $35$. Convert $\frac{3}{7}$ and $\frac{7}{5}$ to fractions with denominator $35$.

$$\frac{15}{35}-\frac{49}{35}$$

Since $\frac{15}{35}$ and $\frac{49}{35}$ have the same denominator, subtract them by subtracting their numerators.

$$\frac{15-49}{35}$$

Subtract $49$ from $15$ to get $-34$.

$$-\frac{34}{35}$$

$-\frac{34}{35} = -0.9714285714285714$