Question

$$\frac{3}{7}^{\frac{\bullet}{8}}$$

Answer

$$8*e*u*l^2*t*37^b$$

Solution


Use Product Rule: \({x}^{a}{x}^{b}={x}^{a+b}\).
\[{37}^{b}u{l}^{2}et\times 8\]
Regroup terms.
\[8eu{l}^{2}t\times {37}^{b}\]