How to solve 3 + 8 12 ૩

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 3 + 8 12 ૩ | Equatix

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$$\frac { 3 } { 8 } + \frac { 1 } { 12 } + \frac { 1 } { 3 }$$

$\frac{19}{24}\approx 0.791666667$

Least common multiple of $8$ and $12$ is $24$. Convert $\frac{3}{8}$ and $\frac{1}{12}$ to fractions with denominator $24$.

$$\frac{9}{24}+\frac{2}{24}+\frac{1}{3}$$

Since $\frac{9}{24}$ and $\frac{2}{24}$ have the same denominator, add them by adding their numerators.

$$\frac{9+2}{24}+\frac{1}{3}$$

Add $9$ and $2$ to get $11$.

$$\frac{11}{24}+\frac{1}{3}$$

Least common multiple of $24$ and $3$ is $24$. Convert $\frac{11}{24}$ and $\frac{1}{3}$ to fractions with denominator $24$.

$$\frac{11}{24}+\frac{8}{24}$$

Since $\frac{11}{24}$ and $\frac{8}{24}$ have the same denominator, add them by adding their numerators.

$$\frac{11+8}{24}$$

Add $11$ and $8$ to get $19$.

$$\frac{19}{24}$$

$\frac{19}{2 ^ {3} \cdot 3} = 0.7916666666666666$