$$\frac{3}{8}+(1\frac{7}{8}-\frac{3}{4})$$
$\frac{3}{2}=1.5$
$$\frac{3}{8}+\frac{8+7}{8}-\frac{3}{4}$$
$$\frac{3}{8}+\frac{15}{8}-\frac{3}{4}$$
$$\frac{3+15}{8}-\frac{3}{4}$$
$$\frac{18}{8}-\frac{3}{4}$$
$$\frac{9}{4}-\frac{3}{4}$$
$$\frac{9-3}{4}$$
$$\frac{6}{4}$$
$$\frac{3}{2}$$
Show Solution
Hide Solution
$\frac{3}{2} = 1\frac{1}{2} = 1.5$
