How to solve 8 पर

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve 8 पर | Equatix

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$$\frac { 3 } { 8 } \times \frac { 18 } { 42 } = \frac { 12 } { 16 }$$

$\text{false}$

Reduce the fraction $\frac{18}{42}$ to lowest terms by extracting and canceling out $6$.

$$\frac{3}{8}\times \frac{3}{7}=\frac{12}{16}$$

Multiply $\frac{3}{8}$ times $\frac{3}{7}$ by multiplying numerator times numerator and denominator times denominator.

$$\frac{3\times 3}{8\times 7}=\frac{12}{16}$$

Do the multiplications in the fraction $\frac{3\times 3}{8\times 7}$.

$$\frac{9}{56}=\frac{12}{16}$$

Reduce the fraction $\frac{12}{16}$ to lowest terms by extracting and canceling out $4$.

$$\frac{9}{56}=\frac{3}{4}$$

Least common multiple of $56$ and $4$ is $56$. Convert $\frac{9}{56}$ and $\frac{3}{4}$ to fractions with denominator $56$.

$$\frac{9}{56}=\frac{42}{56}$$

Compare $\frac{9}{56}$ and $\frac{42}{56}$.

$$\text{false}$$