How to solve (3)/(8)x-4 <= -3

1. Factor the equation (x + 2)(x + 3) = 0. 2. Set each factor equal to zero: x + 2 = 0 and x + 3 = 0. 3. Solve for x: x = -2 and x = -3.

Solve (3)/(8)x-4 <= -3 | Equatix

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$$\frac{ 3 }{ 8 } x-4 \leq -3$$

$x\leq \frac{8}{3}$

Add $4$ to both sides.

$$\frac{3}{8}x\leq -3+4$$

Add $-3$ and $4$ to get $1$.

$$\frac{3}{8}x\leq 1$$

Multiply both sides by $\frac{8}{3}$, the reciprocal of $\frac{3}{8}$. Since $\frac{3}{8}$ is positive, the inequality direction remains the same.

$$x\leq 1\times \frac{8}{3}$$

Multiply $1$ and $\frac{8}{3}$ to get $\frac{8}{3}$.

$$x\leq \frac{8}{3}$$