$$\frac{3}{-3}\times\frac{2\cdot2-6}{-4+6}$$
$1$
$$-\frac{2\times 2-6}{-4+6}$$
$$-\frac{-\left(6-4\right)}{6-4}$$
$$-\left(-1\right)$$
$$1$$
Show Solution
Hide Solution
